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MongoDB Aggregation groupBy with first set of results

I have a collection of documents that look like this:
{
“_id” : ObjectId(“57c3e41816245e29297522b0”),
“id” : “1”,
“created_at” : ISODate(“2014-08-12T09:51:08.308Z”)
}

{
“_id” : ObjectId(“57c3e41816245e29297522c0”),
“id” : “2”,
“created_at” : ISODate(“2014-08-12T09:52:21.629Z”)
}

{
“_id” : ObjectId(“57c3e41816245e29297522d0”),
“id” : “3”,
“created_at” :
0cc13bf012

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python list of lists sort

I have a list of lists:
[
[[10, ‘good’], [20,’very good’]],
[[20, ‘good’], [12,’very good’]],
[[20, ‘good’], [5,’very good’]],
[[12, ‘good’], [10,’very good’]],
]

How can I sort by the first items in the lists?
In this example:
[[10, ‘good’], [20,’very good’]] –> [‘good’,’very good’]
[[20, ‘good’], [12,’very good’]] –> [‘good’,’very good’]
[[20, ‘good’], [5,’very good’]] –> [‘good’,’very good’]
[[12, ‘good’], [10,’very good’]] –> [‘good’,’very good’]

I tried this:
for l in data:
sorted(l, key= lambda x: x[0])
print(l)

But it does not work.

A:

You need to sort the inner list first and then iterate:
data = [
[[10, ‘good’], [20,’very good

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